## Python 100 题 - Day01 # Question 1

### Question:

Write a program which will find all such numbers which are divisible by 7 but are not a multiple of 5,
between 2000 and 3200 (both included).The numbers obtained should be printed in a comma-separated sequence on a single line.

### Hints:

Consider use range(#begin, #end) method.

Main author's Solution: Python 2

``````l=[]
for i in range(2000, 3201):
if (i%7==0) and (i%5!=0):
l.append(str(i))

print ','.join(l)
``````

My Solution: Python 3

• Using for loops
``````for i in range(2000,3201):
if i%7 == 0 and i%5!=0:
print(i,end=',')
print("\b")
``````

• Using generators and list comprehension
``````print(*(i for i in range(2000, 3201) if i%7 == 0 and i%5 != 0), sep=",")
``````

# Question 2

### Question:

Write a program which can compute the factorial of a given numbers.The results should be printed in a comma-separated sequence on a single line.Suppose the following input is supplied to the program: 8
Then, the output should be:40320

### Hints:

In case of input data being supplied to the question, it should be assumed to be a console input.

Main author's Solution: Python 2

``````def fact(x):
if x == 0:
return 1
return x * fact(x - 1)

x = int(raw_input())
print fact(x)
``````

My Solution: Python 3

• Using While Loop

``````n = int(input()) #input() function takes input as string type
#int() converts it to integer type
fact = 1
i = 1
while i <= n:
fact = fact * i;
i = i + 1
print(fact)
``````
• Using For Loop

``````n = int(input()) #input() function takes input as string type
#int() converts it to integer type
fact = 1
for i in range(1,n+1):
fact = fact * i
print(fact)
``````
• Using Lambda Function

``````# Solution by:  harshraj22

n = int(input())
def shortFact(x): return 1 if x <= 1 else x*shortFact(x-1)
print(shortFact(n))
``````

``````'''Solution by: minnielahoti
'''

while True:
try:
num = int(input("Enter a number: "))
break
except ValueError as err:
print(err)

org = num
fact = 1
while num:
fact = num * fact
num = num - 1
print(f'the factorial of {org} is {fact}')
``````

``````'''Soltuion by: KruthikaSR
'''
from functools import reduce

def fun(acc, item):
return acc*item

num = int(input())
print(reduce(fun,range(1, num+1), 1))
``````

# Question 3

### Question:

With a given integral number n, write a program to generate a dictionary that contains (i, i x i) such that is an integral number between 1 and n (both included). and then the program should print the dictionary.Suppose the following input is supplied to the program: 8

Then, the output should be:

``````{1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64}
``````

### Hints:

In case of input data being supplied to the question, it should be assumed to be a console input.Consider use dict()

Main author's Solution: Python 2

``````n = int(raw_input())
d = dict()
for i in range(1,n+1):
d[i] = i * i
print d
``````

My Solution: Python 3:

• Using for loop
``````n = int(input())
ans = {}
for i in range (1,n+1):
ans[i] = i * i
print(ans)
``````
• Using dictionary comprehension
``````n = int(input())
ans={i : i*i for i in range(1,n+1)}
print(ans)
``````

``````'''Solution by: minnielahoti
Corrected by: TheNobleKnight
'''

try:
num = int(input("Enter a number: "))
except ValueError as err:
print(err)

dictio = dict()
for item in range(num+1):
if item == 0:
continue
else:
dictio[item] = item * item
print(dictio)
``````

``````'''Solution by: yurbika
Corrected by: developer-47
'''

num = int(input("Number: "))
print(dict(enumerate([i*i for i in range(1, num+1)], 1)))
``````

## Conclusion

These was the solved problems of day 1. The above problems are very easy for the basic syntex learners.I have shown some easy ways of coding in my solutions. Lets see how to face and attack new problems in the next day.

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